Question

A hollow square shaped tube open at both ends is made of iron the internal square is of 5 cm side and the length of the tube is 8cm there are 192cm^3 of iron in this tube . Find the thickness ​

Answer 1

Answer:

HEYA HERE IS UR ANSWER✌✌❤❤

Cross-sectional area of iron tube = 192 cm³ / 8 cm = 24 cm²

A = s² - 5² = 24 cm²

s² = 25 + 24 = 49 cm²

s = √(49 cm²) = 7 cm

thickness = ½(7 - 5) = 1 cm

Hope This helps :)

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Answer 2

Answer:

hey dear jhanavi here is ur answer......

Step-by-step explanation:

Cross-sectional area of iron tube = 192 cm³ / 8 cm = 24 cm² 

A = s² - 5² = 24 cm² 

s² = 25 + 24 = 49 cm² 

s = √(49 cm²) = 7 cm 

thickness = ½(7 - 5) = 1 cm

hope this will comformly helps u

please mark as brainliest......