A hoop of radius r and mass m rotating with an angular velocity w is placed on a rough horizontal surface. The initial velocity of the centre of the hoop is zero. what will be the velocity of the centre of the hoop when it ceases to slip?
Answers
Answered by
1
Answer:
Explanation:
conservation of angular momentum about a point
′
A
′
Iw
0
=Iw+mvr
And v=wr ( rolling starts )
mr
2
w
0
=mr
2
r
v
+mvr
v=
2
rw
0
Similar questions
History,
4 months ago
Hindi,
4 months ago
Political Science,
9 months ago
Math,
9 months ago
History,
11 months ago