Question

A hoop of radius r and mass m rotating with an angular velocity w is placed on a rough horizontal surface. The initial velocity of the centre of the hoop is zero. what will be the velocity of the centre of the hoop when it ceases to slip?​

Answer 1

Answer:

Explanation:

conservation of angular momentum about a point  

′

A  

′

 

Iw  

0

​  

=Iw+mvr

And v=wr ( rolling starts )

mr  

2

w  

0

​  

=mr  

2

 

r

v

​  

+mvr

v=  

2

rw  

0

​  

 

​