Physics, asked by jsathwik5446, 11 months ago

A horizontal circular loop carries a current that looks clockwise when viewed from above. It is replaced by an equivalent magnetic dipole consisting of a south pole S and a north pole N.
(a) The line SN should be along a diameter of the loop.
(b) The line SN should be perpendicular to the plane of the loop
(c) The south pole should be slow the loop
(d) The north pole should be below the loop

Answers

Answered by rajsingh24
2

Answer:

OPTION B AND D.

Explanation:

Clockwise current is equivalent to a south pole. hence, the SN line should be perpendicular to the plane of the loop with South above the loop and north below it. Thus options B and D are correct.

HOPE IT'S HELPS.......

Answered by bhuvna789456
0

A horizontal circular loop carries a current that looks clockwise when viewed from above. It is replaced by an equivalent magnetic dipole consisting of a south pole S and a north pole N. Therefore the line SN should be perpendicular to the plane of the loop and the north pole should be below the loop

Explanation:

  • A horizontal circular circuit bearing clockwise current functions like a magnet's south pole. Consequently, the magnet's South Pole coincides with the circle. Now, If the current carrying the loop is viewed from above in clockwise direction, it looks as if the magnetic lines of force enter the loop so it acts like a magnet's southern pole. And if we view the loop from below then it seems that magnetic lines of force exit the circle.
  • Therefore the North Pole should be under the ring.

Therefore the Correct answer is Option (b) The line SN should be perpendicular to the plane of the loop and (d) The north pole should be below the loop

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