Question

A long bar magnet has a pole strength of 10 Am. Find the magnetic field at a point on the axis of the magnet at a distance of 5 cm from the north pole of the magnet.

Answer 1

Explanation:

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Answer 2

The magnetic field at a point on the axis of the magnet at a distance of 5 cm from the north pole of the magnet is $4 \times 10^{-4} T$

Explanation:

Step 1:

Given data in the question  

Bar magnet's pole strength, m = 10 A-m

Range from the position of the bar magnet to the north pole, r  = 5 cm = 0.05 m

Step 2:

We know that,  

Due to magnetic charge, the magnetic field is

$B=\frac{\mu_{0}}{4 \pi}=\frac{m}{r^{2}}$

   $=\frac{\left(10^{-7} \times 10\right)}{\left(5 \times 10^{-2}\right)^{2}}$

    $=\frac{\left(10^{-7} \times 10\right)}{25 \times 10^{-4}}$

   $=\frac{\left(10^{-6}\right)}{25 \times 10^{-4}}$

   $=\frac{\left(10^{-2}\right)}{25}$

   $=0.04 \times 10^{-2} \mathrm{T}$

$B=4 \times 10^{-4} T$