Question

A horizontal force of 10N displaces a body of 5 kg along the direction of force 2 m. The
work done by the force will be
(1) 50 J (2) 10 J
(3) 5 J (4) 20 J​

Answer 1

Given :

• Force applied = 10 N
• Mass of the body = 5 kg
• Displacement = 2m

To find :

• Work done by the force

Solution :

The work done by the body is given by ,

$\longrightarrow \boxed{\mathtt{W = F.S \cos \phi}}$

here ,

• W = work done
• F = force
• S = displacement
• Ф = Angle

As the force and displacement both are acting in the same direction

∴ Ф = 0

Hence ,

➜ W = F.S cos 0

➜ W = F.S           (∵ cos 0 = 1)

➜ W = 10 x 2

➜ W = 20 J

The work done by the force is 20 J .

Answer 2

$\huge\underline{\bf \orange{AnSweR :}}$

As the force and displacement both are acting in the same direction.

∴ Ф = 0

Hence ,

=> W = F.S cos 0

=> W = F.S (∵ cos 0 = 1)

=> W = 10 x 2

=> W = 20 J

The work done by the force is 20 J. Ans.