Question

a horizontal force of 5 Newton acting on a body of mass 2 kg at rest, it starts moving on a table having coefficient of friction is 0.2 then find work done by applied force in 5 seconds​

Answer 1

Explanation:

work done = force X distance

acceleration produced on 2 kg mass by 5N force = 5/2 = 2.5

Distance travelled in 5 seconds

s=ut +1/2at2

s= 1/2 x 2.5 x 5 x 5

s=31.25

work done = 31.25 x 5 = 156.25