a+b+c+d+e+f=? if20✓3™=17
Answers
Answer:
Given
A : B : C : D
3 : 4
8 : 10
15 : 17
3 : 4
: 24 : 30
30 : 34
18 :24
24 : 30
30 : 34
Hence
A:B:C:D=18:24:30:34
=9 :12:15:17
I think it is a simple solution for you....
(i) In triangles AEF and CDF, we have
\angle AEF=\angle CDF=90^0∠AEF=∠CDF=90
0
[\because CE\bot AB∵CE⊥AB and AD\bot BCAD⊥BC]
\angle AFE=\angle CFD∠AFE=∠CFD [Vertically opposite angles]
Thus, by AA-criterion of similarity, we have
\triangle AEF\sim \triangle CDF△AEF∼△CDF [Hence \ proved][Hence proved]
(ii) In \triangle 's\quad ABD△
′
sABD and CBECBE, we have
\angle ABD=\angle CBE=\angle B∠ABD=∠CBE=∠B [Common angle]
\angle ADB=\angle CEB=90^0∠ADB=∠CEB=90
0
[\because AD\bot BC∵AD⊥BC and CE\bot ABCE⊥AB]
Thus, by AA-Criterion of similarity, we have
\triangle ABD\sim \triangle CBE△ABD∼△CBE [Hence \ proved][Hence proved]
(iii) In \triangle 's\quad AEF△
′
sAEF and ADBADB, we have
\angle AEF=\angle ADB=90^0∠AEF=∠ADB=90
0
[\because AD\bot BC∵AD⊥BC and CE\bot ABCE⊥AB]
\angle FAE=\angle DAB∠FAE=∠DAB [Common angle]