Question

a horizontal force of 5 newton is required to maintain a velocity of 2 metre per second for a block of 10 kg mass sliding over a rough surface the work done by the force in one minute

Answer 1

Initial velocity u=2 m/s

time=1 minute=1 x 60=60 s

acceleration,a=?

distance,s=?

by using second law of motion

s=ut + 1/2 at square

=2 x 60 + 1/2 a(60)square

=120 + 1/2 a(3600)

=120 + 1800 a

-120=1800 a

-120/1800=1/15=0.066------

Answer 2

yaar nahi aata kya karu