Question

a horizontal jet of water comming out of a pipe of cross section 20 cm square hits a vertical wall with velocity of 10ms and rebounds wih same speed the force exherted by the wall is

Answer 1

volume of water coming out of the pipe = A * v
     = 20 cm² * 10 m/sec
   = 0.02  m³/sec

mass of water hitting the wall  = m = 0.02 m³/sec * 1000 kg/m³
         = 20 kg/sec

As the water hits the wall normal to the wall and gets rebounded at the same speed, the change of momentum of water hitting the wall is:
            = m (v  - (-v))  =  2 m v
           = 2 * 20 kg /sec *  10 m/sec
           =  400 kg-m/sec²

Since, the change of momentum obtained is per unit time,  it is same as the force.  Thus the force acting on the wall by water = force experienced by water jet.

         = 400 Newtons.


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