Question

A horizontal water jet with a velocity of 10 m/s and cross-sectional area of 10 mm2 strikes a fixed plate held normal to the flow direction. Find the total force acting on the plate. (Take density of water, =1000 kg/m3)

Answer 1

Dear Student,

◆ Answer -

F = 1 N

● Explaination -

# Given -

ρ = 1000 kg/cu.m

A = 10 mm² = 10×10^-6 m²

v = 10 m/s

# Solution -

Total force acting on the plate is given by -

F = ρ × A × v²

Substitute values,

F = 1000 × 10×10^-6 × 10^2

F = 1 N

Therefore, the total force acting on the plate is 1 N.

Best luck for exams dear.