A horse is tied to a peg at one corner of a square shaped grass field of side 15 m by means of a 5 m long rope (see the given figure). Find (i) The area of that part of the field in which the horse can graze. (ii) The increase in the grazing area of the rope were 10 m long instead of 5 m. [Use π = 3.14]
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Answered by
18
Answer:
The horse can graze 1/4 the area of a circle of radius L
where L is the length of the rope.
A(5) = pi * 5^2 / 4 = 19.6 m^2
If the rope is twice as long
A(10) = 4 * A(5) = 78.5 m^2 or
A(10) = pi * 10^2 / 4 = 78.5 m^2
Answered by
71
Answer:
The area of that part of the field in which the horse can graze. 19.625 m²
increase in grazing area = 58.875 m²
Step-by-step explanation:
A horse is tied to a peg at one corner of a square shaped grass field
Square has 90 deg angles at sides
so Area covered by horse = (90/360) πr²
= (1/4)(3.14) * 5²
= 19.625 m²
The area of that part of the field in which the horse can graze. 19.625 m²
if rope = 10 cm then Area of Grazing = (1/4)(3.14) * 10² = 78.5 m²
increase in grazing area = 78.5 - 19.625 = 58.875 m²
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