A horse is tied with a rope of length 7 m at one corner of a square field having side equal to 10 m. the minimum possible area of the square field that is left ungrazed is (take, π=22/2)
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Length of the rope is 7 m, thus, the radius is 7 m.
Thus, area of circle = 22/7 *49 = 154 metre squared.
Thus, the quarter of the total area= 154/4= 36m2.
Since, the horse can graze 36 m2
the field left ungrazed is 100-36= 64 m2.
Hope its useful!!!!!!
Thus, area of circle = 22/7 *49 = 154 metre squared.
Thus, the quarter of the total area= 154/4= 36m2.
Since, the horse can graze 36 m2
the field left ungrazed is 100-36= 64 m2.
Hope its useful!!!!!!
Answered by
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Length of the rope is 7 m, thus, the radius is 7 m.
Thus, area of circle = 22/7 *49 = 154 metre squared.
Thus, the quarter of the total area= 154/4= 36m2.
Since, the horse can graze 36 m2
the field left ungrazed is 100-36= 64 m2.
Hope its useful!!!!!!
Mark brainliest
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