A horse pull a wagon with a force of 360 N at an angle 60 with the horizontal at a speed at 10 km+h the power of the horse
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Given: Force=Fcosθ
=360x cos 60⁰
=360x 1/2
=180N
velocity=10km/h
1km/h=5/18 m/s
v=10x5/18 m/s
=2.77m/s
since Power = Fx V
=180 x 2.77
=498.6 W
=360x cos 60⁰
=360x 1/2
=180N
velocity=10km/h
1km/h=5/18 m/s
v=10x5/18 m/s
=2.77m/s
since Power = Fx V
=180 x 2.77
=498.6 W
kvnmurty:
180* 10*5/18= 500 W
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