A hot-air balloon is ascending at the rate of 12 m/s and is 80 m above the ground when a package is dropped over the side. With what speed does it hit the ground?
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Hey Dear,
● Answer -
v = 41.76 m/s
◆ Explanation -
# Given -
u = 12 m/s
s = -80 m
a = -9.8 m/s
# Solution -
Applying Newton's 3rd law of kinematics -
v^2 = u^2 + 2as
v^2 = 12^2 + 2(-10)(-80)
v^2 = 144 + 1600
v^2 = 1744
v = 41.76 m/s
Therefore, the ballon will reach earth with speed of 41.76 m/s.
Thanks for asking..
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