Question

a house costs 36%more today than when it was built . if the cost of the house today is $333200,find its cost when it was built.

Answer 1

Lets its original cost be x.

So, 36% of x =  $\frac{36x}{100}$

So, new cost =  $\frac{36x}{100}$  +  x  =  $\frac{136x}{100}$

But according to ques new cost = $ 333200

So, $\frac{136x}{100}$ = $ 333200

     136 x = $ 33320000

      x = $ 33320000/136

      x = $ 245000

Hence, original value of the house was $245000.

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