Question

If S and T are in the ratio of 3:5, the value of 2S^2+T^2:S^2+T^2 would be in the ratio of?

Answer 1

Answer:

Initial velocity of the body u=0

Distance covered in t

th

second, S

t

=u+

2

1

g(2t−1)

∴ S

t

=0+

2

1

g(2t−1)=

2

1

g(2t−1)

Distance travelled in first second i.e. t=1, S

1

=

2

1

g(2×1−1)=

2

1

g

Distance travelled in 2nd second i.e. t=2, S

2

=

2

1

g(2×2−1)=

2

3

g

Distance travelled in third second i.e. t=3, S

3

=

2

1

g(2×3−1)=

2

5

g

⟹ S

1

:S

2

:S

3

=1:3:5

Answer 2

Answer:

Put S equal to 3 and T equal to 5 as final question is in ratio only.....

18+25/34

43/34

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