Physics, asked by primce7183, 4 months ago

A house hold has four bulbs of 60 W cach. If the bulbs operate for 12 hours daily, Find the
monthly expenditure incurred (30 days). (cost of l unit = 2.50 rupees). Calculate the work done to
increase the velocity of a car from 54 km/h to 126 km/h, if the mass of the car is 898kg.​

Answers

Answered by xXitzSweetMelodyXx
5

Explanation:

Given:-

Power= 60 Watt

Everyday Use = 10 Hours

Total Days= 30

Cost Of elctricity per unit= 3.50 Rs.

Find:-

Total amount to be paid in 30 days

Given:-

The days can be calculated in total hours used in 30 days

Hence, Days x Everyday Use = 30 x 10 = 300 Hours

Convert, 60 Watt into Kwatt = 60/1000

By Formula,

Unit= Kwatt x Time (in hours)

U= 60/1000 x 300

U= 18

Hence, total unit used is 18.

By Formula,

Cost= Unit x Rupees per unit

Cost= 18 x 3.50

Cost= 63 Rupees

Therefore, the amount to pay in 30 days is 63 Rupees.

xXitzSweetMelodyXx

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