Question

A house is installed with 10 bulbs of 60 watt each are used 5 hrs daily.4 fans 75 w each run 10 hrs daily tv 100 w used 2 hrs daily iron of 1000 w 2 hrs daily find monthly cost if per unit cost is 4$

Answer 1

For bulb
Power of 1 bulb = 60 W
Power of 10 bulbs = 600 W = 0.6 Kw
Time = 5 hrs
Energy consumed by bulb= P×T = 0.6×5 = 3 KwH

For fans
Power of 1 fan = 75 W
Power of 4 fans = 150 W = 0.15 Kw
Time = 10 hrs
Energy consumed by fan = P×T = 0.15×10 = 1.5 KwH

For TV
Power of 1 TV = 100 W = 0.1 Kw
Time = 2 hrs
Energy consumed by TV = P×T = 0.1×2 = 0.2 KwH

For iron
Power of 1 iron = 1000 W = 1 Kw
Time = 2 hrs
Energy consumed by iron= P×T = 1×2 = 2 KwH

Total energy consumed in one day = 3 + 1.5 + 0.2 + 2 = 6.7 KwH

Total energy consumed in one month = 6.7×30 = 201 KwH

Cost of 1 KwH = 4$
Cost of 201 KwH = 4×201 = 804$