Question

A house makes a right angle at the window of its opposite. Angle from horizontal to
top is 60°. If the width of street is 6 m, then height of house is​

Answer 1

Step-by-step explanation:

Let C is window in the following figure and AB is a house.  House makes right angle from window C  i.e., ∠ACB = 90° width of street BD = CM = 6 m ∠CBD = 60°, ∠ACM = 90° – 60° = 30° Let AM = x and CD = BM = y From right angled ∆CDB, tan 60° = CD/BD √3 = y/6 or y = 6√3 m From right angled ∆AMC, Hence, height of house  = AB = AM + BM = x + y = 2√3 + 6√3 = 8√3

Answer 2

Step-by-step explanation:

Correct option is

B

8

3

m

Given ∠DBC=60

0

and ∠ADB=90

0

from figure we know that ∠EDB=∠DBC=60

0

Since ∠ADB=∠ADE+∠EDB=90

0

∠ADE=90

0

−60

0

=30

0

From AED ,

tan30=

6

AE

AE−2

3

m

From EDC,

tan60=

6

EB

EB=6

3

m

Height of the house =AE+EB=2

3

+6

3

=8

3

m