Question

A house wife uses a 100 W bulb 8 h a day , and

an electric heater of 300 W for 4 h a day. The

total cost for the month of June at the rate of

0.05 rupee per unit will be

a)Rs 20 b)Rs 25

c) Rs 30 d)Rs 30 paise 50​

Answer 1

Answer:

Bulb: 100W x 8h = 800Wh or 0.8kWh

Heater: 300W x 4h = 1.2 kWh

Adding the both the total will be 2.0kWh per day of operation.

Since this is for month of june,so we have 30 days.

Now multiply by 30 days,

30 x 2 kWh= 60kWh

Each unit of electricity (presumably 1 “unit” is 1kWh) costs 0.5 rupees, so the cost for 30 days will be

60kWh x 0.5 rupees/kWh = 30 rupees.

Explanation:

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Answer 2

Answer:

30 rupees is the answer

Explanation:

Bulb: 100W x 8h = 800Wh or 0.8kWh  

Heater: 300W x 4h = 1.2 kWh    

Adding the both the total will be 2.0kWh per day of operation.  

Since this is for month of june,so we have 30 days.  

Now multiply by 30 days,    

30 x 2 kWh= 60kWh    

Each unit of electricity (presumably 1 “unit” is 1kWh) costs 0.5 rupees, so the cost for 30 days will be

60kWh x 0.5 rupees/kWh = 30 rupees.

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