A household uses the following electric appliances :
1) Refrigerator of rating 400W for 10 hours each day
2) Two electric fans of rating 80W each for 12 hours each day
3) 6 electric tubes of rating 18W each for 6 hours each day
Calculate the electricity bill of the household for the month of June, if the cost per unit of electric energy is Rs.3
Answers
Answer:
Explanation:
=> Here, To calculate the electricity bill of the household for the month of June you need to calculate the usage of appliances for each day
∴ no. of days in June month = 30 Days
=> 1) Refrigerator of rating 400W is run for 10 hours each day
For 30 days, Total usage = 10 * 30 = 300 hours
Energy consumed = 400 * 300 / 1000 = 120 Kwh
=> 2) Two electric fans of rating 80W each run for 12 hours each day
For 30 days, Total usage = 12 * 30 = 360 hours
Energy consumed = 2 * 80 * 360 / 1000 = 57.6 Kwh
=> 3) 6 electric tubes of rating 18W each run for 6 hours each day
For 30 days, Total usage = 6 * 30 = 180 hours
Energy consumed = 6 * 18 * 180 / 1000 = 19.44 Kwh
=> Net Energy consumed in whole month:
120 Kwh + 57.6 Kwh + 19.44 Kwh = 197.04 Kwh
=> ∴ the electric bill = 3 * 197.04 = Rs. 591.12
Therefore, the electricity bill of the household for the month of June is Rs. 591.12.
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