Question

(a) How many mole of atoms are present in 88 gm CO,
(b) What will be the mass of 10 mole of H3,Po4​

Answer 1

Answers:

1. 22/7 moles
2. 980 gm

Explanation:

1.

We know,

Molecular mass of CO = 12+16=28 gm

So 1 mole contains 28 gm CO.

Again, there are 2 atoms in CO.

So we can say that,

28 gm contains = 2 atoms

1 gm. " = 2/28 atoms

88 gm. " = (2x88)/28 atoms

= 44/7 atoms

Now,

2 atoms of CO = 1 mole CO

1 atom of CO = 1/2 mole CO

22/7 atoms of CO = (1x44/7)/2 mole of CO

= 22/7 mole of CO

(Ans.)

2.

We know,

Molecular mass of H3PO4 = 1x3+31x1+16x4

= 98 gm

So 1 mole contains = 98 gm H3PO4

And 10 mole " = 98x10 gm H3PO4

= 980 gm H3PO4

(Ans.)