Question

Raj and Vinay move together by their cars in the same
place. Raj goes with a uniform speed of 10 km/h, Vinay goes with a
8 km/h in the first hour and increases the speed by 2 km in
hour. After how many hours Vinay's car will overtake Raj s Co
run non-stop.
​

Answer 1

Step-by-step explanation:

Speed--10

Then put the eq.2 s=ut+1/2 (at) 2

Answer 2

After 3 hrs hours Vinay's car will overtake Raj’s car if both cars run non-stop.

Step-by-step explanation:

It is given that,

Both Raj and Vinay move together in their respective cars in the same place

The uniform speed of Raj’s car = 10 km/hr

Vinay’s car goes with a speed of 8 km/hr for the first hr then increases by 2 km every hr.  

Let the Vinay’s car overtakes the Raj’s car after “n” hours.

Therefore,

[Distance covered by Raj’s car] = [Distance covered by Vinay’s car]

10n = 8 + [8 + 2] + [8 + (2*2)] + [8 + (3*2)] + ....... + [8 + (n-2)]  

⇒ 10n = 8n + [2*{1 +2 +3 + 4+.......+(n-1)}]

⇒ 2n = 2*[n(n-1)/2]

⇒ n = n(n-1)/2

⇒ 2 = n - 1  

⇒ n = 2 + 1

⇒ n = 3  

Thus, after 3 hours Vinay’s car will overtake Raj’s car.

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