Question

A hundred newton force applied on a block of mass 50 kg produces a constant velocity of 5 metre per minute on rough surface the force of friction exerted on the block will be

Answer 1

Given:

100 N force applied on a block of mass 50 kg produces a constant velocity of 5 metre per minute on rough surface.

To find:

Friction exerted by block.

Calculation:

Since the block is moving with a constant velocity of 5 m/min, it means that the applied force is equal and opposite to the frictional force exerted by the rough surface on the block.

From the Free-Body Diagram:

$\sf{\therefore \: F_{applied} - friction = ma}$

Since , acceleration is zero;

$\sf{ = > \: F_{applied} - friction = m \times 0}$

$\sf{ = > \: F_{applied} - friction = 0}$

$\sf{ = > \: F_{applied} = friction }$

$\sf{ = > \: friction = 100 \: N }$

So, final answer:

$\boxed{ \red{ \large{ \rm{\: friction = 100 \: N }}}}$

Answer 2

Given:

100 N force applied on a block of mass 50 kg produces a constant velocity of 5 metre per minute on rough surface.

To find:

Friction exerted by block.

Calculation:

Since the block is moving with a constant velocity of 5 m/min, it means that the applied force is equal and opposite to the frictional force exerted by the rough surface on the block.

From the Free-Body Diagram:

\sf{\therefore \: F_{applied} - friction = ma}∴Fapplied−friction=ma

Since , acceleration is zero;

\sf{ = > \: F_{applied} - friction = m \times 0}=>Fapplied−friction=m×0

\sf{ = > \: F_{applied} - friction = 0}=>Fapplied−friction=0

\sf{ = > \: F_{applied} = friction }=>Fapplied=friction

\sf{ = > \: friction = 100 \: N }=>friction=100N

So, final answer:

\boxed{ \red{ \large{ \rm{\: friction = 100 \: N }}}}friction=100N