Question

a hunter has a machine gun that can fire 50 g bullets with a velocity of 150 m/s . a 60 kg tiger springs at him with a velocity of 10 m/s . how many bullets must the hunter fire per second into the tiger in order to stop him in his track

Answer 1

This is the answer.

Answer 2

80 bullets must the hunter fire per second into the tiger in order to stop him in his track.

Given,

mass of the bullet, m = 50g = 0.05 kg

velocity of bullet, v = 150 m/s

mass of tiger, M = 60 kg

velocity of tiger, V = 10 m/s

To Find,

No. of bullets to be fired by the hunter

Solution,

We have been given the mass (m) and velocity (v) of the bullet

Therefore, the momentum of the bullet, p is given by:

p = mv

⇒ p = (0.05)(150)

⇒ p = 7.5 kg m/s

Now, we have also been given the mass (M) and velocity (V) of the tiger

Therefore, the momentum of the tiger, P is given by:

P = MV

⇒ p = (60)(10)

⇒ p = 600 kg m/s

Let us assume that the number of bullets fired by the hunter is n

The momentum of the bullets must be equal to the momentum of the tiger in order to stop him on his track

⇒ np = P

⇒ (7.5)n = 600

⇒ n = 600/(7.5)

⇒ n = 80 bullets

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