Question

A hunter of 45 kg is standing on ice fires a bullet of 100
gram with a velocity of 500 ms? by a gun of 5kg. Find
the recoil velocity of the hunter.​

Answer 1

Answer:

The initial momentum of the system,

P1 = momentum of hunter + momentum of gun + momentum of bullet

P1 = 45 × 0 + 5 × 0 + 0.1 ×0....(1)

P2 = 45v + 5v +0.1 × 500

P2 = 50v +50 .....(2)

By the conservation of momentum

p1 = p2

0 = 50v + 50

v = -1 m/s

Answer 2

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