Math, asked by imransulaimani, 11 months ago

A husband's age exceeds that of his wife by
6 years. 10 years ago, the ratio of their ages
was 5:4. Find the present age of the husband.​एक पति की उम्र 6 साल से उसकी पत्नी से अधिक है।10 साल पहले, उनकी आयु का अनुपात 5:4 था।पति की वर्तमान आयु का पता लगाएं xऔर y मान कर लगाए​

Answers

Answered by vskumari9133237228
0

Answer:

here is your answer

Step-by-step explanation:

let,the age of wife =x

age of husband=y

given,

y=x+6_________(1)

y_10/x_10=5/4

4y-40=5x_50

4(x+6)-40=5x_50

4x+24_40=5x_50

4x-16=5x_50

_x=_32

x=34

so the age of wife =34

the age of his husband=34+6

=40

Answered by ajajit9217
0

Answer:

Present age of husband is 40 yrs.

Step-by-step explanation:

Let present age of wife= x yrs.

∴ Present age of husband = x+6

10 yrs ago,

Age of wife = x-10

Age of husband= (x+6)-10

                         = x-4 yrs.

Ratio of husband's age to wife's age=5:4

           (x- 4) : (x-10 ) =5:4

        (x- 4) /(x-10 ) =5/4

By doing cross multiplication ,

4(x- 4) = 5 (x-10)

4x- 16 = 5x -50

5x-4x =50 -16

     x= 34

Present age of wife = 34 yrs.

Present age of husband= 34+6=40 yrs.

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