Question

a hydrated salt mgs04.nh2o undergoes 51 percent loss in weight on heating and becomes anyhrous. value of n is?

Answer 1

Explanation:

Molar mass of Na2SO4 = 142 gm

Percent loss of water from Na2SO4 is 51

So,

$\frac{18n}{142 + 18n} \times 100 = 51 \\ => 1800n = 7242 + 918n \\ => 882n = 7242 \\ => n = \frac{7242}{882} \\ => n = 8.21 mol \\ => n ≈ 9 mol$