A hydrated salt Na2CO3.nH2O retained its 37% mass on heating. What is number of the water of crystallization?
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Given:
The mass retained on heating = 37 %
To Find:
The number of the water of crystallization present in the salt.
Calculation:
- The molar mass of salt:
W = (106 + 18 n) gm .....(i)
- Let us take (106 + 18 n) gm of the salt.
- On heating, we get:
(37/100) × W = 106
⇒ W = 10600/37 = 286.49 gm
- Putting in eqn (i), we get:
286.49 = (106 + 18 n)
⇒ n = (286.49 - 106)/ 18
⇒ n = 180.49/18
⇒ n = 10.027 ≈ 10
- So, the number of the water of crystallization present in the salt is Ten (10).
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