Question

A hydraulic lift is designed to lift heavy objects of maximum mass 2000 kg .the area of cross section of piston carrying the lord is 2.25 * 10-2m2 What is the maximum pressure the smaller Pisto

Answer 1

Explanation:

Pressure on the piston P=

A

F

Force F=m×a

=3000×9.8

=29400 N

Area of cross section A=425×10

−4

sqm

Therefore the pressure P=

425×10

−4

3000×9.8

=6.92×10

5

Pa.

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