Question

a hydraulic machine a force of 10 Newton is applied on the piston of area hundred square centimetre what force is obtained on the other piston of area 500 square metre​

Answer 1

ANSWER:

$F_2$ = 500 × 10³ N

COVERSIONS:

1 m² = 10000 cm²

100 cm² = 0.01 m²

GIVEN:

$F_1$ = 10 N

$A_1$ = 0.01 m²

$A_2$ = 500 m²

TO FIND:

Force on the second piston($F_2$).

FORMULA:

PRESSURE = FORCE / AREA

EXPLANATION:

$P_1$ = $P_1$

$F_1$ / $A_1$ = $F_2$ / $A_2$

10 / 0.01 = $F_2$ / 500

$F_2$ = 10 × 100 × 500

$F_2$ = 500 × 10³ N

Hence force on the second piston($F_2$) = 500 × 10³ N