Question

A hydraulic press consists of two cylinders of cross-sectional area 0.2m2 and 5.0m2 . The piston in the smaller area is pushed down with a force of 100N through a distance of 0.2m. Calculate:
i) the pressure transmitted by the fluid ii) the pressure exerted by the piston in the large cylinder iii) the distance moved by the piston in the larger cylinder.

Answer 1

TOPIC :- PASCAL'S LAW

CONCEPT :- The fluid pressure is transmitted equally in all direction.

SOLUTIONS

We have,

pressure at smaller piston = F/A = 100/0.2 = 500 N/m²

Thus, by pascal's law

the pressure exerted by the fluid = the pressure exerted by the piston in the larger cylinder = 500 N/m³.

Now,

volume of liquid coming down in smaller piston side = volume of liquid going up in larger piston side.

=> a1 × d1 = a2 × d2

=> 0.2 × 0.2 = 5 × d2

=> d2 = 0.008 m.

Thus, required answer is

(I) = 500 N/m²

(ii) 500 N/m²

(iii) 0.008 m