Physics, asked by akinlabibesto, 9 months ago

A hydraulic press consists of two cylinders of cross-sectional area 0.2m2 and 5.0m2 . The piston in the smaller area is pushed down with a force of 100N through a distance of 0.2m. Calculate:
i) the pressure transmitted by the fluid ii) the pressure exerted by the piston in the large cylinder iii) the distance moved by the piston in the larger cylinder.

Answers

Answered by Draxillus
8

TOPIC :- PASCAL'S LAW

CONCEPT :- The fluid pressure is transmitted equally in all direction.

SOLUTIONS

We have,

pressure at smaller piston = F/A = 100/0.2 = 500 N/

Thus, by pascal's law

the pressure exerted by the fluid = the pressure exerted by the piston in the larger cylinder = 500 N/.

Now,

volume of liquid coming down in smaller piston side = volume of liquid going up in larger piston side.

=> a1 × d1 = a2 × d2

=> 0.2 × 0.2 = 5 × d2

=> d2 = 0.008 m.

Thus, required answer is

(I) = 500 N/m²

(ii) 500 N/m²

(iii) 0.008 m

Similar questions