A hydraulic press consists of two cylinders of cross-sectional area 0.2m2 and 5.0m2 . The piston in the smaller area is pushed down with a force of 100N through a distance of 0.2m. Calculate:
i) the pressure transmitted by the fluid ii) the pressure exerted by the piston in the large cylinder iii) the distance moved by the piston in the larger cylinder.
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TOPIC :- PASCAL'S LAW
CONCEPT :- The fluid pressure is transmitted equally in all direction.
SOLUTIONS
We have,
pressure at smaller piston = F/A = 100/0.2 = 500 N/m²
Thus, by pascal's law
the pressure exerted by the fluid = the pressure exerted by the piston in the larger cylinder = 500 N/m³.
Now,
volume of liquid coming down in smaller piston side = volume of liquid going up in larger piston side.
=> a1 × d1 = a2 × d2
=> 0.2 × 0.2 = 5 × d2
=> d2 = 0.008 m.
Thus, required answer is
(I) = 500 N/m²
(ii) 500 N/m²
(iii) 0.008 m
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