Question

In a hydraulic press, an effort of 50N Is applied to the piston to raise a load of 500N. If this effort piston has an area of 5 cm2, what is the area of the load piston?

Answer 1

TOPIC :- PASCAL'S LAW

CONCEPT :- The fluid pressure is transmitted equally in all direction.

FORMULA

F1/A1 = F2/A2. (F1 - effort piston , F2 - load piston)

SOLUTIONS

Given,

F1 = 50 N

F2 = 500 N.

A1 = 5 cm²

A2 = ?

Applying the formula F1/A1 = F2/A2

= > 50/5 = 500/A2

°> A2 = 50 cm²

Hence, area of load piston is 50 cm².