Question

a hydraulic press has a large piston with a cross-sectional area is 250 cm square and a small piston with a cross sectional area is 1.25cm square what is the force on a large piston when 1250n force is applied to the small piston

Answer 1

Answer:

hello mate here your answer

Explanation:

Pressure exerted on both sides should be same on ideal conditions.

So, P = Force/Area should be same on either pistons.

Thus, (1 denotes larger.)

P1 = P2

F1/A1 = F2/A2

F1/250 = 1250/1.25

F1 = 250 × 1000 = 250000 Newtons

or F1 = 2.5 × 10^5 Newtons