A hydraulic turbine has a discharge of 3 m/s when operating under a head of 15m and a speed 500 rpm. If it is to operate under 12mhead, the rotational speed will be 11 600 rpm 2) 559 rpm 3) 447 rpm 4) 400 rpm
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Answer:
400 rpm
Explanation:
Velocity = sqrt 2*g*h & pi*d*N*.
So N is proportionate to Sqrt h,
N1/sqrt h1= N2/sqrt h2
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