Math, asked by ghulevivek0, 1 month ago

The un
(a) 40,319
40,320
The number of arrangements of 10 different things taken 4 at a time in which one particu
thing always occurs is
3x8 x 7 x
(a) 2015
120
2016
(c) 2014
(d) none of these
The number of permutations of 10 different things taken 4 at a time in which one particular
thing never occurs is
(a) 3,020
(b) 3,025
(d) none of these
3,024ع
gx 87 7x6​

Answers

Answered by anirudhkaushik100
3

Answer:

2016

Step-by-step explanation:

Total Permutations of n different things taken r at a time when a particular item is always included in the arrangement is :

r * (n-1 p r-1).

so ,

4*(10–1 p 3)

= 4* (9 p 3)

= 4*9*8*7

=2016.

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