Question

A hydrocabon has 92.3% carbon and 7.7 % hydrogen the molecular mass the compond empirical formula of the hydrocarbon

Answer 1

heya--

Imagine that you have 100 g of Carbon and hydrogen

Convert % into mass ⇒

92.3%→92.3g
7.7%→7.7g

Transform mass into moles ⇒

(The molar mass of carbon and hydrogen are rounded here)

C:=92.3/12.01= 7.69mol

H=:7.7/1.01=7.62mol

To see for one Carbon, how many Hydrogen you have, put the next equation ⇒

17.69=x7.62

(It can be the other way around, for 1 Hydrogen, how many Carbon)

17.62=x7.69

Solves for x ⇒

(Generally take the largest of those result and divide it by the smallest ) ⇒

7.697.62=1.01≅1

It means that for 1 Hydrogen, you have 1 Carbon each time.

Empirical formula≡CH.............

TYSM@kundan

Answer 2

Imagine that you have 100 g of Carbon and hydrogen

Convert % into mass ⇒

92.3%→92.3g
7.7%→7.7g

Transform mass into moles ⇒

(The molar mass of carbon and hydrogen are rounded here)

C:92.312.01=3,7.69mol

H:7.71.01=3 ,7.62mol

To see for one Carbon, how many Hydrogen you have, put the next equation ⇒

17.69=x7.62

(It can be the other way around, for 1 Hydrogen, how many Carbon)

17.62=x7.69

Solves for x ⇒

(Generally take the largest of those result and divide it by the smallest ) ⇒

7.697.62=1.01≅1

It means that for 1 Hydrogen, you have 1 Carbon each time.

Empirical formula≡CH