A hydrocarbon X adds on one mole of hydrogen to give another hydrocarbon and decolourised bromine water. X
react with KMnO4 in presence of acid to give two mole of the same carboxylic acid. The structure of X is:
a) CH3CH = CHCH2CH2CH3
b) CH3CH2CH = CHCH2CH3
c) CH3CH2CH2—CH = CHCH3
d) CH2 = CH—CH2CH2CH3
Answers
Answer:
Answer B is correct
Explanation:
The reaction of a process:
CH
3
CH
2
CH=CHCH
2
CH
3
+Br
2
⟶CH
3
CH
2
CHBr−CHBrCH
2
CH
3
And in presence of acidic KMnO
4
alkene is oxidised to form acid.
CH
3
CH
2
CH=CHCH
2
CH
3
+(H
2
O+O)⟶2CH
3
CH
2
COOH
So the structure of X is CH
3
CH
2
CH=CHCH
2
CH
3
Since it gives two moles of same carboxylic acid on reaction with oxidizing agent potassium permanganate hence it must be symmetrical alkene. Here the only alkene in option B is symmetrical alkene. Thus option B is correct.
X reacts with KMnO_(4) in presenece of acid to give two moles of the same carboxylic acid.The structure of X is: ... A hgydrocarbon X adds on one mole of hydrogen to gives another hydrocarbon and also decolourises bromine water.