A hydroelectric power station takes its water from a lake whose water level is 50 m above turbine . assuming an overall efficiency of 40%,calculate mass of water which must flow through turbine each second to produce power output of 1 mega watt
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As we know that
P=E/t
where p is power , t is time and e is the potential energy(mgh)
Now we know that g = 10 m/s
h= 50 m
t=1 sec
Therefore,
mgh=P
m=P/gh
m= 400000/10 x 50
m=800 kg.
P=E/t
where p is power , t is time and e is the potential energy(mgh)
Now we know that g = 10 m/s
h= 50 m
t=1 sec
Therefore,
mgh=P
m=P/gh
m= 400000/10 x 50
m=800 kg.
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