Physics, asked by ishaansinha9877, 6 months ago

A hydrogen atom is at the earth's surface, the electron and proton in the atom are separated by a distance of 5.29 x 10∧11. what is the ratio of the magnitude of electrical force exerted by the proton and the electron to the weight of the electron

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Answered by ajajahmad9438
0

Answer:

Thus the Coulomb force is F = 8.19 × 10−8 N. This is also an attractive force, although it is traditionally shown as positive since gravitational force is always attractive. The ratio of the magnitude of the electrostatic force to gravitational force in this case is, thus, FFG=2.27×1039 F F G = 2.27 × 10 39 .

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