Question

a hydrogen atom is excited to the n =8 energy level it emits a photon of light as it falls to the n = 2 energy level.calculate the frequency of the light emitted​

Answer 1

Answer:

The frequency of the light emitted is 833.33×10^8 Hz.

Explanation:

Given: n1 = 8

           n2 = 2

To find: Frequency of the light emitted

Solution:

According to the Rydberg's equation,

1/λ = R [1/n1^2 - 1/n2^2]

1/λ = 109677 cm^-1 [1/8² - 1/2²]

1/λ = 274.19m^-1

λ = 0.0036 m

Therefore, wavelength is 0.0036 m.

Now, frequency is given by:

f = v/λ      

 (∵ Frequency = Speed of light/ Wavelength)

f = 3×10^8ms^-1 / 0.0036 m

f = 833.33×10^8 Hz

Therefore, the frequency of the light emitted is 833.33×10^8 Hz.

https://brainly.in/question/37436446

https://brainly.in/question/37369805

#SPJ1