A hydrogen filled balloon ascending at the rate of 18 kmph was drifted by wind. Its angle of elevation at 10th and 15th minutes were found to be 60° and 45° respectively. The wind speed (in whole numbers) during the last five minutes, approximately, is equal to
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Average wind speed = w = (d₂ - d₁)/(t₂ - t₁)
y₁ = vt₁ = 3km; y₂ = vt₂ = 4.5km
tan(60) = sqrt(3) = y₁/d₁; d₁ = y₁/sqrt(3)
tan(45) = 1 = y₂/d₂; d₂ = y₂
d₂ - d₁ = y₂ - y₁/sqrt(3) = 4.5 km – 3 km/1.732 = 2.77 km
w = (2.77 km)/(5 min) = 9.22 m/s
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Average wind speed = w = (d₂ - d₁)/(t₂ - t₁)
y₁ = vt₁ = 3km; y₂ = vt₂ = 4.5km
tan(60) = sqrt(3) = y₁/d₁; d₁ = y₁/sqrt(3)
tan(45) = 1 = y₂/d₂; d₂ = y₂
d₂ - d₁ = y₂ - y₁/sqrt(3) = 4.5 km – 3 km/1.732 = 2.77 km
w = (2.77 km)/(5 min) = 9.22 m/s
☑️HOPE IT HELPS☑️
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