a hydrogen like system has ionization energy 11808 kj/mol. find the number of protons in the nucleus of the system.
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The number of proton are 3
Explanation:
- Ionization energy is defined as the energy which is released when a valence electron is ejected out of an isolated gaseous atom.
- The formula used to calculate ionization energy follows:
- En = - 1312 x z^2 / n^2 K J / mol
Where
Z = atomic number
n = Energy level
The transition of ionization energy is from
We are given:
En = 11808 KJ/ mol
Putting values in above equation, we get:
11808 = (-1313 x z^2 / ∞^2 ) - ( - 1312 x z^2 / 1^2)
11808 = 1312 x z^2
Z = 3
Hence the number of proton are 3
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