Question

A hypothetical element X is found to have an atomic mass of 37.45 amu. Element X has only
two isotopes, X-37 and X-38. The X-37 isotope has a fractional abundance of 0.7721 and an
isotopic mass of 37.24. What is the isotopic mass of the other isotope?

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

The isotopic mass of the other element is 38.16 u.

Explanation:

We know,

Average atomic mass = ∑(Atomic mass of an isotope) × (Fractional abundance)

or, 37.45 = (37.24 × 0.7721) + ( $x$ × 0.2279)   {Since 1 - 0.7721 = 0.2279}

or, 37.45 = 28.753 + ( $x$ × 0.2279)

or, $x$ × 0.2279 = 37.45 - 28.753 = 8.697

or, $x$ = $\frac{8.697}{0.2279}$ = 38.16

Hence, the isotopic mass of the other element is 38.16 u.