Question

a+ib=1+i/1-i =a2+b2=1
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Answer 1

Step-by-step explanation:

a+ib=1+i/1-i.........(i)

conjugate of equation (i) is

a-ib= 1-i/1+i.....(ii)

now , (i)×(ii)

(a+ib)(a-ib)=1+i/1-i× 1-i/1+i

=a²-(ib)²=1

=a²+b²=1