Question

A) If th=(2n-1) for an A.P. 1, 3, 5, 7, .... (2n-1); then find 30th term of A.P.
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Answer 1

Answer:

a = 1

d = 2

tn = a + ( n - 1 )d

   = 1 + 2 x 29

   = 1 + 58

   = 59

Hence the 30th term of AP is 59.

Answer 2

The 30th term of the given AP($a_{30}$) is equal to 59.

Step-by-step explanation:

The given arithmetic progration(AP):

1, 3, 5, 7, ........ ,(2n - 1)

Here, first term (a) = 1, common difference(d) = 3 - 1 = 2 and

the number of terms (n) = 30

To find, 30th term of the given AP($a_{30}$) = ?

We know that,

The nth term of the AP

$a_{n} =a+(n-1)d$

30th term of the given AP($a_{30})$

= 1 + (30 - 1) × 2

= 1 + 29 × 2

= 1 + 58

= 59

∴ The 30th term of the given AP($a_{30}$) = 59

Thus, the 30th term of the given AP($a_{30}$) is equal to 59.