If tqo zeros of the quadratic polynomial x2 +(a+2)x+b are 3 and 4,find the values of a and b
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Answered by
5
Answer:
Let the polynomial be denoted as P(x).
P(x) = x² + (a + 2)x + b
As per the question, 3 and 4 are the zeroes of the polynomial.
P(3) =0
=> 3² + (a + 2)3 + b = 0
=> 9 + 3a + 6 + b = 0
=> 3a + b + 15 = 0 .....eq.(1)
Again,
P(4) = 0
=> 4² + (a + 2)4 + b = 0
=> 16 + 4a + 8 + b = 0
=> 4a + b + 24 = 0 .....eq.(2)
Eq.(2) - Eq(1) = 0
=> a + 9 = 0
=> a = -9
Putting value of "a" in eq.(1)
3a + b + 15 = 0
=> 3 (-9) + b + 15 = 0
=> b - 27 + 15 = 0
=> b = 12
Final answer :
- a = -9
- b = 12
Answered by
13
Hey!
Good question ✒
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