a. If X = 5Y = 8Z, find X:Y:Z.
b. If 2A = 5B = 7C, find A:B:C
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Answer a. —
Let x = 5y = 8z be = k
Then, x = k
5y =k OR y = k/5
8z = k. OR z = k/8
Therefore, x : y : z = k : k/5 : k/8
= 1 : 1/5 : 1/8
(L.C.M. of 5 and 8 = 40)
Multiplying 40 in numerator, we get-
40 : 40/5 : 40/8
= 40 : 8 : 5
Therefore, x : y : z = 40 : 8 : 5
Let x = 5y = 8z be = k
Then, x = k
5y =k OR y = k/5
8z = k. OR z = k/8
Therefore, x : y : z = k : k/5 : k/8
= 1 : 1/5 : 1/8
(L.C.M. of 5 and 8 = 40)
Multiplying 40 in numerator, we get-
40 : 40/5 : 40/8
= 40 : 8 : 5
Therefore, x : y : z = 40 : 8 : 5
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