a) In parallelogram ABCD, two points X and Y are taken on diagonal AC such that AX-CY. Prove that
(DAADX = ABYC (1) DX-BY.
D
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Since BXDY is a parallelogram .
∴ XO = YO --- (i)
DO = BO --- (ii)
[∵ diagonals of a parallelogram bisect each other ]
But AX = CY --- (iii) [given]
Adding (i) and (iii) , we have
XO + AX = YO + CY
⇒ AO = CO ---(iv)
From (ii) and (iv) , we have
AO = CO and DO = BO
Thus, ABCD is a parallelogram , because diagonals AC and BD bisect each other at O.
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