Question

A
In the adjoining figure, ABCD is a quadrilateral in which
AB=AD and BC=DC. Prove that AC bisects each of the
B
angles A and
с C​

Answer 1

Answer:

∠ABC and∠ADC

AB=AD

BC=DC

AC=AC

so triangle ABC = triangle ADC.

BAE=∠DAE

∠BAE=∠DAE

AC is a bisector of ∠A

2)BE=BD

∠ABEand∠AED

BE=ED

AB=AD

AE=AE

∠ABE≅∠AED(SSS)

So, ∠AED=∠AEB

∠AEB+∠AED=1800

∠AEB=900.

Step-by-step explanation: